20z^2-17z+3=0

Solution for 20z^2-17z+3=0 equation:

20z^2-17z+3=0

a = 20; b = -17; c = +3;
Δ = b2-4ac
Δ = -172-4·20·3
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-7}{2*20}=\frac{10}{40}
=1/4
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+7}{2*20}=\frac{24}{40}
=3/5
$